A bag holds 11 beads 7 of the beads are red the rest are white two beads are taken at random work out the probability that one one bead of each colour is taken
Accepted Solution
A:
Answer:Probability=28/55Step-by-step explanation:Given a total of 11 beads of which 7 beads are red and 4 beads are white.There are four possibilities for each of the outcomes namely red+red white+red white +white red+white.By total probability theorem we get that Probability = [tex]\frac{P(red+white)+P(white+red) }{P(red+red)+P(white+red)+P(white +white)+P(red+white).}[/tex]P(red+red)=[tex]7/11*6/10[/tex]P(white+red)=[tex]4/11*7/10[/tex]P(white +white)=[tex]4/11*3/10[/tex]P(red+white)=[tex]7/11*4/10[/tex]Probability=[tex]\frac{4/11*7/10 + 7/11*4/10}{7/11*6/10+4/11*3/10+4/11*7/10 + 7/11*4/10}[/tex]Probability=[tex]56/110[/tex]=[tex]28/55[/tex]