Y varies directly as x. Y=42 when x=6. Find the value of y when x =15.
Accepted Solution
A:
Answer:y=120Step-by-step explanation:Y varies directly as x is written as[tex]y \alpha x[/tex]introducing a constanty=kxfrom the question, when y=48, x=6substitute it in the formula48=6kmaking k the subject by dividing through by 6[tex] \frac{48}{6} = \frac{6k}{6} [/tex]k=48/6k=8put the value of k in the expression y=kxy=8xfrom the question,the value of y when x=15 is given byy=8Γ15y=120.